PQR ~ LTR. In PQR, PQ = 4.2 cm, QR = 5.4 cm, PR = 4.8 cm. Construct PQR and LTR, such that PQ/ LT = 3/4 .
Given PQR and LTR are similar.Corresponding angles will be equal.PRQ LRTGiven PQ/LT = 3/4PQ/LT = QR/TR = PR/LR [Corresponding sides of similar triangles]PQ/LT= QR/TR = PR/LR = 3/4Sides of LTR are longer than corresponding sides of PQR.Steps of construction:1. Draw ∆PQR such that PQ = 4.2 , QR = 5.4 , and PR = 4.8. […]
ABC ~ LMN. In ABC, AB = 5.5 cm, BC = 6 cm, CA = 4.5 cm. Construct ABC and LMN such that BC /MN = 5/ 4 .
Rough figure is shown below. Given ABC and LMN are similar.their corresponding sides are proportional.AB/LM = BC/MN = AC/LNGiven BC/MN = 5/4AB/LM = BC/MN = AC/LN = 5/4As the sides AB, BC and AC are known we can find lengths of sides LM,MN and LN.Given AB = 5.5 , BC = 6 , CA = […]