Given A man borrows = Rs. 8000
Repay with total interest = Rs 1360
In 12 months, thus n = 12
Thus, S12 = 8000 + 1360 = 9360
Each installment being less than preceding one
Thus, d = – 40
We need to find “a”
Now, by using sum of nth term of an A.P. we will find its sum
Thus, last installment tn = 560