Question:

A person is standing at a distance of 80m from a church looking at its top. The angle of elevation is of 45°. Find the height of the church.

Answer:

Maharashtra board Sol class 10 maths p2 chapter 6-1

Let C represent position of person and AB represent height of the church.
Angle of elevation = C = 45˚
BC = 80m
In right angled triangle ABC , tan = tan 45˚ = AB/BC
1 = AB/80
AB = 80
Hence height of the church is 80m.

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A person is standing at a distance of 80m from a church looking at its top. The angle of elevation is of 45°. Find the height of the church.

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