Given r1 = 20cm
r2 = 15cm
Height , h = 21cm
Volume of frustum ,V = (1/3)h(r12+r22+r1×r2)
V = (1/3)×(22/7)×21×(202+152+20×15)
V = 22×(400+225+300)
V = 22×925
V = 22×925
= 20350cm3
= 20.34litres [∵ 1 litre = 1000cm3]
Hence the capacity of the tub is 20.34 litres.