A washing tub in the shape of a frustum of a cone has height 21 cm. The radii of the circular top and bottom are 20 cm and 15 cm respectively. What is the capacity of the tub ?( = 22/7)


Given r1 = 20cm
r2 = 15cm
Height , h = 21cm
Volume of frustum ,V = (1/3)h(r12+r22+r1×r2)
V = (1/3)×(22/7)×21×(202+152+20×15)
V = 22×(400+225+300)
V = 22×925
V = 22×925
= 20350cm3
= 20.34litres [∵ 1 litre = 1000cm3]
Hence the capacity of the tub is 20.34 litres.

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