Given points are P(-12,-3) and Q(4, k).
x1 = -12 , y1 = -3 , x2 = 4 , y2 = k
Slope of line PQ = (y2-y1)/ (x2-x1)
= (k-(-3))/(4-(-12)
= (k+3)/16
Given slope of line passing through P and Q is 1/2.
½ = (k+3)/16
2(k+3) = 16
k+3 = 8
k = 8-3 = 5
Hence the value of k is 5.