Find the 19th term of the following A.P.7, 13, 19, 25, . . .

Given A.P. is 7, 13, 19, 25, . . .
Where first term a = 7
Second term t₁ = 13
Third term t₂ = 19
Common Difference d = t₂ – t₁ = 19 – 13 = 6
We know that, n^th term of an A.P. is
t_n = a + (n – 1) d
We need to find the 19^th term,
Here n = 19
Thus, t₁₉ = 7 + (19 – 1) × 6
t₁₉ = 7 + (18) × 6 = 7 + 108 = 115
Thus, t₁₉ = 115