Find the 27th term of the following A.P.

Given A.P. is 9, 4, – 1, – 6, – 11, . . .
Where first term a = 9
Second term t₁ = 4
Third term t₂ = – 1
Common Difference d = t₂ – t₁ = – 1 – 4 = – 5
We know that, n^th term of an A.P. is t_n = a + (n – 1) d
We need to find the 27^th term,
Here n = 27
Thus, t₂₇ = 9 + (27 – 1) × (– 5)
t₂₇ = 9 + (26) × (– 5) = 9 – 130 = – 121
Thus, t₂₇ = – 121