Let the co-ordinates of P be (x, y).
A(-1,7) and B(4,-3) are the given points.
x1 = -1 , y1 = 7 , x2 = 4 , y2 = -3 , m = 2 and n = 3
By Section formula x = (mx2+nx1)/(m+n)
x = (2×4+3×-1)/(2+3)
x = (8-3)/5
x = 5/5
x= 1
By Section formula y = (my2+ny1)/(m+n)
y = (2×-3+3×7)/5
y = (-6+21)/5
y = 15/5
y = 3
Hence the co-ordinate of point P is (1,3).