(1) The persons of O- blood group are 40%. The classification of persons based on blood groups is to be shown by a pie diagram. What should be the measures of angle for the persons of O- blood group?
A. 114°
B. 140°
C. 104°
D. 144°
Solution:
D. 144°
Explanation:
![Maharashtra Board Solutions for Class 10 Maths Part 1 Chapter 6 Maharashtra Board Solutions for Class 10 Maths Part 1 chapter 6 - Image 36](https://cdn1.byjus.com/wp-content/uploads/2020/04/maharashtra-board-solutions-for-class-10-maths-part-1-chapter-6-image-36.png)
(2) Different expenditures incurred on the construction of a building were shown by a pie diagram. The expenditure
Rs 45,000 on cement was shown by a sector of central angle of 75°. What was the total expenditure of the construction?
A. 2,16,000
B. 3,60,000
C. 4,50,000
D. 7,50,000
Solution:
A. 2,16,000
Explanation:
![Maharashtra Board Solutions for Class 10 Maths Part 1 Chapter 6 Maharashtra Board Solutions for Class 10 Maths Part 1 chapter 6 - Image 37](https://cdn1.byjus.com/wp-content/uploads/2020/04/maharashtra-board-solutions-for-class-10-maths-part-1-chapter-6-image-37.png)
(3) Cumulative frequencies in a grouped frequency table are useful to find . . .
A. Mean
B. Median
C. Mode
D. All of these
Solution:
B. Median
Explanation:
Median is the middle value of the set of ordered data. The position of the median is given by {(n + 1)/2}th value, where n is the number of values in a set of data.
![Maharashtra Board Solutions for Class 10 Maths Part 1 Chapter 6 Maharashtra Board Solutions for Class 10 Maths Part 1 chapter 6 - Image 38](https://cdn1.byjus.com/wp-content/uploads/2020/04/maharashtra-board-solutions-for-class-10-maths-part-1-chapter-6-image-38.png)
Solution:
![Maharashtra Board Solutions for Class 10 Maths Part 1 Chapter 6 Maharashtra Board Solutions for Class 10 Maths Part 1 chapter 6 - Image 39](https://cdn1.byjus.com/wp-content/uploads/2020/04/maharashtra-board-solutions-for-class-10-maths-part-1-chapter-6-image-39.png)
Explanation:
Among the given option, (Xi – A)/g is the correct option.
Where Xi = values in the given data corresponding to ith position.
A = Assumed mean
g = class size
Thus, (C) is the correct option.
![Maharashtra Board Solutions for Class 10 Maths Part 1 Chapter 6 Maharashtra Board Solutions for Class 10 Maths Part 1 chapter 6 - Image 40](https://cdn1.byjus.com/wp-content/uploads/2020/04/maharashtra-board-solutions-for-class-10-maths-part-1-chapter-6-image-40.png)
The median of the distances covered per litre shown in the above data is in the group . . .. .
A. 12-14
B. 14-16
C. 16-18
D. 18-20
Solution:
C. 16-18
Explanation:
Here, (n/2)th = (50/2)th = 25th term
cf = 23 < 25 ⇒ Median class = 16-18
Median class is the next class of interval of cumulative frequency.
Thus, option (C) is correct.
![Maharashtra Board Solutions for Class 10 Maths Part 1 Chapter 6 Maharashtra Board Solutions for Class 10 Maths Part 1 chapter 6 - Image 41](https://cdn1.byjus.com/wp-content/uploads/2020/04/maharashtra-board-solutions-for-class-10-maths-part-1-chapter-6-image-411.png)
The above data is to be shown by a frequency polygon. The coordinates of the points to show number of students in the class 4-6 are . . . .
A. (4, 8)
B. (3, 5)
C. (5, 8)
D. (8, 4)
Solution:
C. (5, 8)
Explanation:
![Maharashtra Board Solutions for Class 10 Maths Part 1 Chapter 6 Maharashtra Board Solutions for Class 10 Maths Part 1 chapter 6 - Image 42](https://cdn1.byjus.com/wp-content/uploads/2020/04/maharashtra-board-solutions-for-class-10-maths-part-1-chapter-6-image-42.png)
So, the coordinates of the points to show number of students in the class 4-6 are (5,8).
Thus, option (C) is correct.