**(1) The persons of O- blood group are 40%. The classification of persons based on blood groups is to be shown by a pie diagram. What should be the measures of angle for the persons of O- blood group?A. 114°B. 140°C. 104°D. 144°**

**Solution:**

D. 144°**Explanation:**

**(2) Different expenditures incurred on the construction of a building were shown by a pie diagram. The expenditureRs 45,000 on cement was shown by a sector of central angle of 75°. What was the total expenditure of the construction?A. 2,16,000B. 3,60,000C. 4,50,000D. 7,50,000**

**Solution:**

A. 2,16,000**Explanation:**

**(3) Cumulative frequencies in a grouped frequency table are useful to find . . .A. Mean**

**B. MedianC. ModeD. All of these**

**Solution:**

B. Median**Explanation:**

Median is the middle value of the set of ordered data. The position of the median is given by {(n + 1)/2}^{th} value, where n is the number of values in a set of data.

**Solution:**

**Explanation:**

Among the given option, (X_{i} – A)/g is the correct option.

Where X_{i} = values in the given data corresponding to i^{th} position.

A = Assumed mean

g = class size

Thus, (C) is the correct option.

**The median of the distances covered per litre shown in the above data is in the group . . .. .A. 12-14B. 14-16C. 16-18D. 18-20**

**Solution:**

C. 16-18**Explanation:**

Here, (n/2)^{th} = (50/2)^{th} = 25^{th} term

cf = 23 < 25 ⇒ Median class = 16-18

Median class is the next class of interval of cumulative frequency.

Thus, option (C) is correct.

**The above data is to be shown by a frequency polygon. The coordinates of the points to show number of students in the class 4-6 are . . . .A. (4, 8)B. (3, 5)C. (5, 8)D. (8, 4)**

**Solution:**

C. (5, 8)**Explanation:**

So, the coordinates of the points to show number of students in the class 4-6 are (5,8).

Thus, option (C) is correct.