AB = AC [Given ]
BAC = BCA [Angles opposite to equal sides of an isosceles triangle are equal]
AB = BC = 1/√2× AC [By 45˚ – 45˚-90˚ theorem]
=(1/√2) ×√8
=(1/√2) × 2√2
= 2
AB = BC ….____
BAC = _____
AB = BC = ____× AC
= ____ ×√8
= ____ × 2√2
= ____
AB = AC [Given ]
BAC = BCA [Angles opposite to equal sides of an isosceles triangle are equal]
AB = BC = 1/√2× AC [By 45˚ – 45˚-90˚ theorem]
=(1/√2) ×√8
=(1/√2) × 2√2
= 2
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