Proof:
![](https://ai-shiksha.com/wp-content/uploads/2024/02/maharashtra-board-sol-class-10-maths-p2-chapter-2-16.png)
In PRM
Given MQ = QR = a
Q is the midpoint of MR .
PQ is the median.
PR2+PM2 = 2PQ2+2QM2 [Apollonius theorem]
a2+PM2 = 2a2+2a2
PM2 = 3a2
PM = √3a…………(i)
![](https://ai-shiksha.com/wp-content/uploads/2024/02/maharashtra-board-sol-class-10-maths-p2-chapter-2-17.png)
In PQN
Given NR = QR = a
R is the midpoint of QN.
PR is the median.
PN2+PQ2 = 2PR2+2RN2 [Apollonius theorem]
PN2+a2 = 2a2+2a2
PN2 = 3a2
PN = √3a…………..(ii)
From (i) and (ii) PM = PN = √3×a
Hence proved.