Question:

From the information given in the figure 2.31, prove that PM = PN = √3×a

Answer:

Proof:

In PRM
Given MQ = QR = a
Q is the midpoint of MR .
PQ is the median.
PR2+PM2 = 2PQ2+2QM2 [Apollonius theorem]
a2+PM= 2a2+2a2
PM2 = 3a2
PM = √3a…………(i)

In PQN
Given NR = QR = a
R is the midpoint of QN.
PR is the median.
PN2+PQ2 = 2PR2+2RN2 [Apollonius theorem]
PN2+a= 2a2+2a2
PN2 = 3a2
PN = √3a…………..(ii)
From (i) and (ii) PM = PN = √3×a
Hence proved.

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