Given Arithmetic Progression 12, 16, 20, 24, . . . Find the 24th term of this progression.

Given A.P. is 12, 16, 20, 24, . . .
Where first term a = 12
Second term t₁ = 16
Third term t₂ = 20
Common Difference d = t₂ – t₁ = 20 – 16 = 4
We know that, n^th term of an A.P. is t_n = a + (n – 1) d
We need to find the 24^th term,
Here n = 24
Thus, t₂₄ = 12 + (24 – 1) × 4
t₂₄ = 12 + (23) × 4 = 12 + 92 = 104
Thus, t₂₄ = 104