If A (1, -1),B (0, 4),C (-5, 3) are vertices of a triangle then find the slope of each side.

A (1, -1),B (0, 4),C (-5, 3) are the given points.
Slope of line AB = (y₂-y₁)/ (x₂-x₁)
= (4-(-1))/(0-1)
= 5/-1 = -5
Slope of line BC = (y₂-y₁)/ (x₂-x₁)
= (3-4)/(-5-0)
= -1/-5 = 1/5
Slope of line AC = (y₂-y₁)/ (x₂-x₁)
= (3-(-1))/(-5-1)
= 4/-6 = -2/3
Hence the slopes of the sides AB, BC and AC are -5, 1/5 , -2/3 respectively.