Question:

If cot = 40/9 , find the values of cosec and sin.

Answer:

Given cot = 40/9
We have 1+cot² = cosec²
1+(40/9)² = cosec²
1+(1600/81) = cosec²
(81+1600)/81 = cosec²
1681/81 = cosec²
cosec² = 1681/81
Taking square root on both sides
cosec = 41/9
We have sin = 1/cosec
sin = 1÷(41/9)
sin = 9/41
Hence cosec = 41/9 and sin = 9/41.

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If cot = 40/9 , find the values of cosec and sin.

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