If sec = 13/12 , find the values of other trigonometric ratios

Given sec = 13/12
cos = 1/sec = 12/13
We have 1+tan² = sec²
1+ tan² = (13/12)²
tan² = (13/12)²-1 = (169/144)-1 = (169-144)/144 = 25/144
Taking square root on both sides
tan = 5/12
cot = 1/tan = 12/5
sin/cos = tan
sin = tan×cos
sin = (5/12)×(12/13)
sin = 5/13
cosec = 1/sin = 13/5
Hence cos = 12/13 , tan = 5/12, cot = 12/5 , sin = 5/13 and cosec = 13/5