Question:

If tan = 2, find the values of other trigonometric ratios.

Answer:

Given tan = 2
We have 1+tan2 = sec2
1+22 = sec2
sec2 = 5
Taking square root on both sides
sec =√5
cos = 1/sec = 1/√5
tan = sin/cos
2 = sin÷(1/√5)
sin = 2/√5
cosec = 1/sin
coesc = √5/2
cot= 1/tan
cot = 1/2
Hence sin = 2/√5, cosec = √5/2, cos = 1/√5, sec = √5 and cot = 1/2

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