In adjoining figure 1.14 seg PS ⊥ seg RQ, seg QT ⊥ seg PR. If RQ = 6, PS = 6 and PR = 12, then find QT.

Given PS ⊥ RQ and QT ⊥ PR.
RQ = 6
PS = 6
PR = 12
Area of PQR with base PR and height QT = (1/2)×PR×QT
Area of PQR with base QR and height PS = (1/2)×QR×PS
A(PQR)/ A(PQR) = (1/2)×PR×QT /(1/2)×QR×PS
1 = PR×QT/ QR×PS
1 = 12×QT/6×6
6×6 = QT×12
QT = 36/12
QT = 3
Hence measure of side QT is 3 units.