Question:

In adjoining figure PQ ⊥ BC, AD ⊥ BC then find following ratios.

(i) A( PQB) /A( PBC)
(ii) A(PBC) / A( ABC)
(iii) A( ABC) /A( ADC)
(iv) A( ADC) /A( PQC)

Answer:

(i) PQB and PBC have same height PQ.
Ratio of areas of triangles with equal heights are proportional to their corresponding bases.
A(PQB )/A(PBC) = BQ/BC

(ii) PBC and ABC have same base BC.
Ratio of areas of triangles with equal bases are proportional to their corresponding heights.
A(PBC) / A( ABC) = PQ/AD

(iii) ABC) and ADC have equal heights AD.
Ratio of areas of triangles with equal heights are proportional to their corresponding bases.
A( ABC) /A( ADC) = BC/DC

(iv) Ratio of areas of two triangles is equal to the ratio of the products of their bases and corresponding heights.
A( ADC) /A( PQC) = DC×AD/QC×PQ

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