In figure 1.13 BC⊥ AB, AD⊥ AB, BC = 4, AD = 8, then find A(ABC) /A( ADB) .


Here ABC and ADB have the same base AB.
Areas of triangles with equal bases are proportional to their corresponding heights.
Since bases are equal, areas are proportional to heights.
Given BC = 4 and AD = 8
So, A(ABC) /A( ADB) = BC/AD
= 4/8
= 1/2
Hence ratio of areas of ABC and ADB is 1:2.

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