Question:

In figure 1.75, A – D – C and B – E – C seg DE || side AB If AD = 5, DC = 3, BC = 6.4 then find

BE.

Maharashtra board Sol class 10 maths p2 chapter 1-31

 

Answer:

Given DE AB.
AD/DC = BE/EC [Basic proportionality theorem]
AD = 5, DC = 3, BC = 6.4 [Given]
BE = x , EC = 6.4-x [Given]
5/3 = x/(6.4-x)
Cross multiplying we get
5×(6.4-x) = 3× x
32-5x = 3x
32 = 8x
x = 32/8 = 4
Hence BE = 4 units.

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