Question:

In figure 2.18, QPR = 90°, seg PM ⊥ seg QR and Q-M-R, PM = 10, QM = 8, find QR.

Answer:

In PQR , QPR = 90˚
seg PM ⊥ seg QR [Given]
PM² = QM×MR [Theorem of geometric mean]
10² = 8×MR
MR = 100/8 = 12.5
QR = QM + MR
QR = 8+12.5 = 20.5
Hence measure of QR is 20.5 units.

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In figure 2.18, QPR = 90°, seg PM ⊥ seg QR and Q-M-R, PM = 10, QM = 8, find QR.

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