Question:

In figure 3.77, ray PQ touches the circle at point Q. PQ = 12, PR = 8, find PS and RS.

Answer:

Given PQ = 12 , PR = 8
PQ is a tangent to the circle.
PQ² = PR ×PS
12² = 8×PS
PS = 144/8
PS = 18
PS = PR+RS
RS = PS-PR
RS = 18-8 = 10
Hence PS = 18 units and RS = 10 units.

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In figure 3.77, ray PQ touches the circle at point Q. PQ = 12, PR = 8, find PS and RS.

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