Question:

In figure 3.86, circle with centre M touches the circle with centre N at point T.

Radius RM touches the smaller circle at S. Radii of circles are 9 cm and 2.5 cm. Find the answers to the following questions hence find the ratio MS:SR.

(1) Find the length of segment MT
(2) Find the length of seg MN
(3) Find the measure of NSM.

Answer:

(1) Given radius of bigger circle is 9cm.
Length of segment MT = 9cm.
(2) MT = MN+NT [M-N-T]
9 = MN+2.5 [Given radius of smaller circle is 2.5]
MN = 9-2.5
MN = 6.5cm.
(3) RM touches smaller circle at S.

MR is the tangent to the smaller circle. NS is the radius of smaller circle.
NSM = 90˚ [Tangent theorem]
In NSM , NS2+MS= MN2
2.52+MS2 = 6.52
MS2 = 6.52-2.52
MS2 = 42.25-6.25
MS2 = 36
MS = 6
MR = SR+SM [R-S-M]
9 = SR+6
SR = 9-6 = 3
MS:SR = 6:3 = 2:1

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