In figure 7.35, PQRS is a rectangle. If PQ = 14 cm, QR = 21 cm, find the areas of the parts x, y and z.

Given PQ = 14cm
QR = 21cm
Q = = 90˚
Area of part x = (/360)r²
Area of part x = (90/360)×(22/7)×14²
= 11×14
= 154cm²
Consider sector (R-BYA)
QR = QB+BR
BR = 21-14 = 7cm
AR = 7cm [radius of same circle]
Area of part y = (/360)r²
Area of part y = (90/360)×(22/7)×7²
= 11×7/2
= 38.5cm²
Area of rectangle PQRS = length ×breadth
= QR×PQ
= 21×14
= 294cm²
Area of part z = Area of rectangle PQRS – [Area of part x+ Area of part y]
Area of part z = 294-(154+38.5)
= 294-192.5
= 101.5cm²
Hence area of part x is 154cm² , area of part y is 38.5cm² and area of part z is 101.5cm²