Given PQ = 14cm
QR = 21cm
Q = = 90˚
Area of part x = (/360)r2
Area of part x = (90/360)×(22/7)×142
= 11×14
= 154cm2
Consider sector (R-BYA)
QR = QB+BR
BR = 21-14 = 7cm
AR = 7cm [radius of same circle]
Area of part y = (/360)r2
Area of part y = (90/360)×(22/7)×72
= 11×7/2
= 38.5cm2
Area of rectangle PQRS = length ×breadth
= QR×PQ
= 21×14
= 294cm2
Area of part z = Area of rectangle PQRS – [Area of part x+ Area of part y]
Area of part z = 294-(154+38.5)
= 294-192.5
= 101.5cm2
Hence area of part x is 154cm2 , area of part y is 38.5cm2 and area of part z is 101.5cm2