Question:

In figure1.55, ABC = 75°, EDC = 75° state which two triangles are similar and by which test? Also write the similarity of these two triangles by a proper one to one correspondence.

Answer:

Given ABC = 75˚ , EDC = 75˚
Consider ABC and EDC
ABC = EDC [Given ABC = 75˚ , EDC = 75˚]
ACB = DCE [Common angle]
ABC ~ EDC [AA test of similarity]
One to one correspondence is ABC↔ EDC

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