Given ABC = 75˚ , EDC = 75˚
Consider ABC and EDC
ABC = EDC [Given ABC = 75˚ , EDC = 75˚]
ACB = DCE [Common angle]
ABC ~ EDC [AA test of similarity]
One to one correspondence is ABC↔ EDC
Given ABC = 75˚ , EDC = 75˚
Consider ABC and EDC
ABC = EDC [Given ABC = 75˚ , EDC = 75˚]
ACB = DCE [Common angle]
ABC ~ EDC [AA test of similarity]
One to one correspondence is ABC↔ EDC
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