In the figure 7.31, radius of the circle is 7 cm and m(arc MBN) = 60°, find

Given radius of circle , r = 7cm
(1) Area of the circle , A = r²
= (22/7)×7²
=( 22/7)×49
= 154cm²
Hence the area of the circle is 154cm²

(2)Given m(arc MBN), = 60°
Area of sector = (/360)r²
A(O-MBN) = (60/360)×(22/7)×7²
= (1/6)×22×7
= 25.67cm²
Hence area of sector O-MBN is 25.67cm²

(3) Area of major sector = Area of circle -Area of minor sector
A(O-MCN) = 154-25.67
= 128.33cm²
Hence area of sector O-MCN is 128.33cm²