Question:

In the figure 7.44, O is the centre of the circle. m(arc PQR) = 60° OP = 10 cm. Find the area of the shaded region. ( = 3.14, √3 = 1.73)

Answer:

Given radius OP , r = 10cm
m(arc PQR) , = 60°
Area of segment PQR = r²[(/360) – (sin/2)]
= 10²[3.14×(60/360)- sin60˚/2]
= 100[3.14×(1/6)- √3/4]
= 100[(3.14/6)- 1.73/4]
= (314/6)-(173/4)
= 52.33- 43.25
= 9.08cm²
Hence area of shaded region is 9.08cm².

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In the figure 7.44, O is the centre of the circle. m(arc PQR) = 60° OP = 10 cm. Find the area of the shaded region. ( = 3.14, √3 = 1.73)

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