Question:

In the figure 7.45, if A is the centre of the circle. PAR = 30°, AP = 7.5, find the area of the segment PQR ( = 3.14)

Answer:

Given radius AP , r = 7.5
Central angle PAR = = 30
Area of segment PQR = r²[(/360) – (sin/2)]
= 7.5²[3.14×(30/360)- sin30˚/2]
= 56.25[3.14×(1/12)- 1/4]
= 56.25[(3.14/12)- (3/12)]
= 56.25×0.14/12
= 0.65625cm²
Hence area of segment PQR is 0.65625cm².

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In the figure 7.45, if A is the centre of the circle. PAR = 30°, AP = 7.5, find the area of the segment PQR ( = 3.14)

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