Let Monday be the first term i.e. a = t1
Let Tuesday be the second term that is t2
Let Wednesday be the third term that is t3
Let Thursday be the fourth term that is t4
Let Friday be the fifth term that is t5
Let Saturday be the sixth term that is t6
Given: t1 + t6 = 5 + (t2 + t6)
⇒ a = 5 + (t2 + t6) – t6
⇒ a = 5 + t2 …. (1)
We know that,
Now, by using nth term of an A.P. formula
tn = a + (n – 1) d
where n = no. of terms
a = first term
d = common difference
tn = nth terms
Thus, t2 = a + (2 – 1) d
⇒ t2 = a + d
Now substitute value of t2 in (1) we get,
⇒ a = 5 + (a + d)
⇒ d = a – 5 – a = – 5
Given: t3 = – 30°
Thus, t3 = a + (3 – 1) × (– 5)
⇒ – 30 = a + 2 × (– 5)
⇒ – 30 = a – 10
⇒ a = – 30 + 10 = – 20°
Thus, Monday, a = t1 = – 20°
Using formula tn + 1 = tn + d
We can find the value of the other terms
Tuesday, t2 = t1 + d = – 20 – 5 = – 25°
Wednesday, t3 = t2 + d = – 25 – 5 = – 30°
Thursday, t4 = t3 + d = – 30 – 5 = – 35°
Friday, t5 = t4 + d = – 35 – 5 = 40°
Saturday, t6 = t5 + d = – 40 – 5 = – 45°
Thus, we obtain an A.P.
– 20°, – 25°, – 30°, – 35°, – 40°, – 45°