LMN is an equilateral triangle. LM = 14 cm. As shown in figure, three sectors are drawn with vertices as centres and radius7 cm. Find,

(1) Given LMN is an equilateral triangle .
LM = 14 cm
Area of LMN = (√3/4)a²
Here a represents the side of equilateral triangle.
a = 14
Area of LMN = (√3/4)×14²
= 49√3
= 84.87cm²
Hence area of LMN is 84.87cm²

(2) Since LMN is equilateral, L = M = N = 60˚
= 60˚
Given r = 7
Area of sector = (/360)r²
Area of sector = (60/360)×22/7×7²
= 11×7/3
= 25.67cm²
Hence area of one sector = 25.67cm²

(3)Total area of 3 sectors = 3×area of one sector
= 3×25.67
= 77.01cm²
Hence total area of 3 sectors is 77.01cm².

(4)Area of shaded region = Area of LMN – Area of 3 sectors
= 84.87 – 77.01
= 7.86cm²
Hence area of shaded region is 7.86cm².