Question:

Mahendra and Virat are sitting at a distance of 1 metre from each other. Their masses are 75 kg and 80 kg, respectively. What is the gravitational force between them? Given : r = 1 m, m1 = 75 kg, m2 = 80 kg and G = 6.67 x 10 -11 Nm2/kg2..

Answer:

As per the Newton’s law F = Gm₁m₂ /r²

Replace the equation with values

Then, F= 6.67 x 10 ^-11x 75 x 80/ 1² N = 4.002 x 10^-7 N

Hence, the gravitational force between Mahendra and Virat is 4.002 x 10^-7 N

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Mahendra and Virat are sitting at a distance of 1 metre from each other. Their masses are 75 kg and 80 kg, respectively. What is the gravitational force between them? Given : r = 1 m, m1 = 75 kg, m2 = 80 kg and G = 6.67 x 10 -11 Nm2/kg2..

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