Observe the measures of pots in figure 7.8 and 7.9. How many jugs of water can the cylindrical pot hold ?

Given radius of jug , r = 3.5 cm
Height of jug , h = 10 cm
Volume of conical jug, V = (1/3)r²h
= (1/3)××3.5²×10 = (122.5/3)×
Given Radius of pot ,R = 7cm
Height of pot, H = 10 cm
Volume of pot = R²H
= ×7²×10 = 490
Number of jugs of water the cylindrical pot can hold = Volume of pot/Volume of conical jug
= 490 ÷ (122.5/3)×
= 490×(3/122.5)
= 12
Hence the pot can hold 12 jugs of water.