Point P is the centre of the circle and AB is a diameter . Find the coordinates of point B if coordinates of point A and P are (2, -3) and (-2, 0) respectively.


Given co-ordinates of P = (-2,0) = (x,y)
Co-ordinates of A = (2,-3) = (x1, y1)
Let co-ordinates of B = (x2,y2)
Since P is the midpoint of diameter AB ,
By midpoint formula x = (x1+x2)/2
-2 = 2+x2/2
x= -4-2
x= -6
y = (y1+y2)/2
0 = (-3+y2)/2
-3+y2 = 0
y2 = 3
Hence the co-ordinates of point B is (-6,3).

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