According to the question we can form an A.P.
5000, 7000, 9000, ……
Hence, the first term a = 5000
Second term t1 = 7000
Third term t2 = 9000
Thus, common difference d = t2 – t1 = 9000 – 7000 = 2000
Here, number of terms n = 12
We need to find S12
Now, by using sum of nth term of an A.P. we will find its sum
Where, n = no. of terms
a = first term
d = common difference
Sn = sum of n terms
Thus, on substituting the given value in formula we get,
⇒S12 = 6 × [ 10,000 + 11 × 2000]
⇒S12 = 6 × [10,000 + 22,000]
⇒S12 = 6 × 32,000
⇒S12 = Rs. 192000