(1) In ABC and PQR, in a one to one correspondence AB/QR = BC/ PR = CA/ PQ then
(A) PQR ~ ABC
(B) PQR ~ CAB
(C) CBA ~ PQR
(D) BCA ~ PQR
![](https://ai-shiksha.com/wp-content/uploads/2024/02/maharashtra-board-sol-class-10-maths-p2-chapter-1-21.png)
Given AB/QR = BC/ PR = CA/ PQ
By SSS test of similarity , PQR ~ CAB .
Correct option is (B).
(2) If in DEF and PQR, D Q, R E then which of the following statements is
false?
(A) EF/PR = DF/ PQ
(B) DE/ PQ = EF/ RP
(C) DE/ QR = DF /PQ
(D) EF/ RP = DE/ QR
![Maharashtra board Sol class 10 maths p2 chapter 1 Maharashtra board Sol class 10 maths p2 chapter 1-22](https://cdn1.byjus.com/wp-content/uploads/2020/04/maharashtra-board-sol-class-10-maths-p2-chapter-1-22.png)
Solution:
Given D Q, R E
DEF ~QRP…. [AA test of similarity]
DE/QR = EF/RP = DF/QP [Corresponding sides of similar triangles]
DE/ PQ ≠ EF/ RP
Hence option (B) is false.
(3) In ABC and DEF B = E, F = C and AB = 3DE then which of the statements
regarding the two triangles is true?
(A)The triangles are not congruent and not similar
(B)The triangles are similar but not congruent.
(C)The triangles are congruent and similar.
(D) None of the statements above is true.
![Maharashtra board Sol class 10 maths p2 chapter 1 Maharashtra board Sol class 10 maths p2 chapter 1-23](https://cdn1.byjus.com/wp-content/uploads/2020/04/maharashtra-board-sol-class-10-maths-p2-chapter-1-23.png)
Solution:
Given B = E
F = C
ABC ~DEF [AA test of similarity]
Hence option B is the true statement.
(4) ABC and DEF are equilateral triangles, A (ABC):A(DEF)=1:2
If AB = 4 then what is length of DE?
(A)2√2
(B)4
(C)8
(D)4√2
![Maharashtra board Sol class 10 maths p2 chapter 1 Maharashtra board Sol class 10 maths p2 chapter 1-24](https://cdn1.byjus.com/wp-content/uploads/2020/04/maharashtra-board-sol-class-10-maths-p2-chapter-1-24.png)
Solution:
Given A (ABC):A(DEF) = 1:2
ABC and DEF are equilateral triangles.
A = D [Angle equals 60˚]
B = E [Angle equals 60˚]
ABC ~ DEF [AA test of similarity]
A (ABC):A(DEF) = AB2/DE2 [Theorem of areas of similar triangles]
1/2 = 42/DE2
Taking square root on both sides
1/√2 = 4/DE
DE = 4√2
Hence option (D) is the correct answer.
(5) In figure 1.71, seg XY || seg BC, then which of the following statements is true?
(A) AB / AC = AX / AY
(B) AX / XB = AY / AC
(C) AX / YC = AY / XB
(D) AB / YC = AC / XB
![Maharashtra board Sol class 10 maths p2 chapter 1 Maharashtra board Sol class 10 maths p2 chapter 1-25](https://cdn1.byjus.com/wp-content/uploads/2020/04/maharashtra-board-sol-class-10-maths-p2-chapter-1-25.png)
Solution:
Given seg XY || seg BC
AX/BX = AY/YC [Basic proportionality theorem]
(BX/AX ) +1 = (YC/AY) +1
(BX+AX)/AX = (YC+AY)/AY
AB/AX = AC/AY
AB/AC = AX/AY
Hence correct option is (A).