Question:

Solve the following equations by Cramer’s method.

(1) 6x – 3y = –10; 3x + 5y – 8 = 0

(2) 4m – 2n = –4; 4m + 3n = 16

(4) 7x + 3y = 15; 12y – 5x = 39

Maharashtra Board Solutions for Class 10 Maths Part 1 Chapter1 - Image 87

 

 

 

Answer:

(1) 6x – 3y = –10; 3x + 5y – 8 = 0

Solution:

Maharashtra Board Solutions for Class 10 Maths Part 1 Chapter1 - Image 2

(2) 4m – 2n = –4; 4m + 3n = 16

Solution:

Maharashtra Board Solutions for Class 10 Maths Part 1 Chapter1 - Image 83
Maharashtra Board Solutions for Class 10 Maths Part 1 Chapter1 - Image 84

Solution:

Maharashtra Board Solutions for Class 10 Maths Part 1 Chapter1 - Image 85

∴ (x, y) = (1/2, -1/2)

(4) 7x + 3y = 15; 12y – 5x = 39

Solution:

Maharashtra Board Solutions for Class 10 Maths Part 1 Chapter1 - Image 86
Maharashtra Board Solutions for Class 10 Maths Part 1 Chapter1 - Image 87

Solution:

Maharashtra Board Solutions for Class 10 Maths Part 1 Chapter1 - Image 88
Maharashtra Board Solutions for Class 10 Maths Part 1 Chapter1 - Image 89

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