(1) x2 + x – 20 = 0
(2) x2 + 2x – 5 = 0
(3) m2 – 5m = -3
(4) 9y2 – 12y + 2 = 0
(5) 2y2 + 9y + 10 = 0
(6) 5x2 – 4x + 7 = 0
(1) x2 + x – 20 = 0
Solution:
(2) x2 + 2x – 5 = 0
Solution:
(3) m2 – 5m = -3
Solution:
(4) 9y2 – 12y + 2 = 0
Solution:
Given
9y2 – 12y + 2 = 0
The above equation can be written as
(3y)2 – 2 × 3y × 4 + (4)2 – (4)2 + 2 = 0
(3y)2 – 2 × 3y × 4 + (4)2 – 16 + 2 = 0
(3y – 4)2 – 14 = 0
(3y – 4)2 = 14
3y – 14 = ±√143y = 14 ± √14y = (14 ± √14)/3
(5) 2y2 + 9y + 10 = 0
Solution:
(6) 5x2 – 4x + 7 = 0
Solution:
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