![Maharashtra Board Solutions for Class 10 Maths Part 1 Chapter3 Maharashtra Board Solutions for Class 10 Maths Part 1 Chapter 2 - Image 20](https://cdn1.byjus.com/wp-content/uploads/2020/04/maharashtra-board-solutions-for-class-10-maths-part-1-chapter-2-image-201.png)
⇒ a + 27d = 60 …… (1)
We need to find value of 28th term that is t28
Now, by using nth term of an A.P. formula
tn = a + (n – 1) d
where n = number of terms
a = first term
d = common difference
tn = nth terms
we can find value of t28 by substituting all the value in formula we get,
⇒ t28 = a + (28 – 1) d
⇒ t28 = a + 27 d
From equation (1) we get,
⇒ t28 = a + 27 d = 60
⇒ t28 = 60