Circumference1 = 2r1 = 132
r1 = 132/2 = ____
Circumference2 = 2r2 = 88
r2 = 88/2 = ____
Slant height of frustum l = √[h2+(r1-r2)2]
= √[__2+(___)2]
= ____cm
Curved surface area of frustum = (r1+r2)l
= ×___×___
= ___sq.cm.
Circumference1 = 2r1 = 132
r1 = 132/2 = 21cm [=22/7]
Circumference2 = 2r2 = 88
r2 = 88/2 = 14cm
Slant height of frustum l = √[h2+(r1-r2)2]
= √[242+(21-14)2] [given h =24]
= √[576+(7)2]
= √[576+49]
= √625
= 25cm
Curved surface area of frustum = (r1+r2)l
= ×(21+14)×25
= ×(35)×25
= 2750sq.cm
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