Question:

The distances covered by 250 public transport buses in a day is shown in the following frequency distribution table. Find the median of the distances.

Maharashtra Board Solutions for Class 10 Maths Part 1 chapter 6 - Image 55

Answer:

Let us prepare cumulative frequency table:

Maharashtra Board Solutions for Class 10 Maths Part 1 chapter 6 - Image 56

Here, N = 250
N/2 = 250/2 = 125
Since, cumulative frequency 180 is just greater than 125. ⇒ median class = 220-230
Median is given by

Maharashtra Board Solutions for Class 10 Maths Part 1 chapter 6 - Image 57

Where l = lower limit of the median class
N = Sum of frequencies
h = class interval of the median class
cf = Cumulative frequency of the class preceding the median class
f = Frequency of the median class
Here, Median class = 220-230
L = 220
N/2 = 125
h = 10
cf = 100
f = 80
Putting all these values in the median formula, we get

Maharashtra Board Solutions for Class 10 Maths Part 1 chapter 6 - Image 58

⇒ Median = 220 + 250/80
⇒ Median = 220 + 3.125 = 223.125
Or Median is approximately 223.13 km
Thus, median of the distances is 223.13 km.

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