The radii of ends of a frustum are 14 cm and 6 cm respectively and its height is 6 cm. Find its

Given r₁ = 14cm
r₂= 6cm
Height , h = 6cm
Slant height of frustum l = √[h²+(r₁-r₂)²]
= √[6²+(14-6)²]
= √[36+(8)²]
= √[36+64]
= √100 = 10

(i) Curved surface area of frustum = l(r₁+r₂)
= ×10(14+6)
= ×10×20
= 3.14 ×200
= 628cm²
Hence curved surface area of frustum is 628cm².

(ii) Total surface area of frustum = l (r₁+ r₂)+r₁²+r₂²
= ×10(14+ 6)+×14²+×6²
= ×10×20+×196+×36
= 200+196+36
= 432
= 432×3.14
= 1356.48cm²
Hence Total surface area of frustum is 1356.48cm².

(iii)Volume of frustum = (1/3)h(r₁²+r₂²+r₁×r₂)
= (1/3)×6(14²+6²+14×6)
= 2×(196+36+84)
= 2×3.14×316
= 1984.48cm³
Hence volume of frustum is 1984.48cm³