(1) 10 and -10
(2) 1–3√5 and 1 + 3√5
(3) 0 and 7
(1) 10 and -10
Solution:
Let α = 10 and β = -10
∴ α + β = 10 – 10 = 0 α β = 10(-10) = – 100
Quadratic equation is
x2 – (α + β) x + α β = 0
⇒ x2 – 0(x) – 100 = 0
⇒ x2 – 100 = 0
(2) 1–3√5 and 1 + 3√5
Solution:
(3) 0 and 7
Solution:
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