(1) 2y = 10 – y2
(2) (x-1)2 = 2x + 3
(3) x2 + 5x = – (3-x)
(4) 3m2 = 2m2 – 9
(5) P (3 + 6p) = – 5
(6) x2 – 9 = 13
(1) 2y = 10 – y2
Given
2y = 10 – y2
2y + y2 – 10 = 0
y2 + 2y – 10 = 0;
a = 1, b = 2, c = -10
(2) (x-1)2 = 2x + 3
Solution:
(3) x2 + 5x = – (3-x)
Solution:
(4) 3m2 = 2m2 – 9
Solution:
(5) P (3 + 6p) = – 5
Solution:
(6) x2 – 9 = 13
Solution:
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